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133. Clone Graph
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Given a reference of a node in a connected undirected graph.
Return a deep copy (clone) of the graph.
Each node in the graph contains a value (int) and a list (List[Node]) of its neighbors.
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class Node: def init(self, val = 0, neighbors = None): self.val = val self.neighbors = neighbors if neighbors is not None else []
Test case format:
For simplicity, each node’s value is the same as the node’s index (1-indexed). For example, the first node with val == 1, the second node with val == 2, and so on. The graph is represented in the test case using an adjacency list.
An adjacency list is a collection of unordered lists used to represent a finite graph. Each list describes the set of neighbors of a node in the graph.
The given node will always be the first node with val = 1. You must return the copy of the given node as a reference to the cloned graph.
Example 1:
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Input: adjList = [[2,4],[1,3],[2,4],[1,3]] Output: [[2,4],[1,3],[2,4],[1,3]] Explanation: There are 4 nodes in the graph. 1st node (val = 1)'s neighbors are 2nd node (val = 2) and 4th node (val = 4). 2nd node (val = 2)'s neighbors are 1st node (val = 1) and 3rd node (val = 3). 3rd node (val = 3)'s neighbors are 2nd node (val = 2) and 4th node (val = 4). 4th node (val = 4)'s neighbors are 1st node (val = 1) and 3rd node (val = 3).
Example 2:
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Input: adjList = [[]] Output: [[]] Explanation: Note that the input contains one empty list. The graph consists of only one node with val = 1 and it does not have any neighbors.
Example 3:
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Input: adjList = [] Output: [] Explanation: This an empty graph, it does not have any nodes.
Example 4:
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Input: adjList = [[2],[1]] Output: [[2],[1]]
回傳dfs 走訪記錄
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T:O(n), S:O(n) class Solution: def cloneGraph(self, node: 'Node') -> 'Node': def dfs(node): if node in visited: return visited[node] visited[node] = Node(node.val) for nei in node.neighbors: visited[node].neighbors.append(dfs(nei)) return visited[node] # simply return, no node if not node: return None visited = {} clone_graph = dfs(node) return clone_graph