This is a place to put my clutters, no matter you like it or not, welcome here.
0%
207. Course Schedule
Posted onEdited onIn面試Views: Symbols count in article: 1.2kReading time ≈1 mins.
There are a total of numCourses courses you have to take, labeled from 0 to numCourses - 1. You are given an array prerequisites where prerequisites[i] = [ai, bi] indicates that you must take course bi first if you want to take course ai.
For example, the pair [0, 1], indicates that to take course 0 you have to first take course 1.
Return true if you can finish all courses. Otherwise, return false.
Example 1:
1 2 3 4
Input: numCourses = 2, prerequisites = [[1,0]] Output: true Explanation: There are a total of 2 courses to take. To take course 1 you should have finished course 0. So it is possible.
Example 2:
1 2 3 4
Input: numCourses = 2, prerequisites = [[1,0],[0,1]] Output: false Explanation: There are a total of 2 courses to take. To take course 1 you should have finished course 0, and to take course 0 you should also have finished course 1. So it is impossible.
# T:O(nˆ2), S:O:(n) class Solution: def canFinish(self, numCourses: int, prerequisites: List[List[int]]) -> bool: n = numCourses graph = [[] for _ in range(n)] g = [0] * n for v, u in prerequisites: print(v,u) graph[u].append(v) g[v] += 1 S = [ v for v in range(n) if g[v] == 0] while S: u = S.pop() for v in graph[u]: g[v] -= 1 if g[v] == 0: S.append(v) return not any(g)